Two forces, one four times as large as the other, pull in the same direction on a 10kg mass and impart to it an acceleration of 2.5 m/s2. If the smaller force is removed, what is the acceleration of the mass?

Respuesta :

Answer:

The acceleration of the mass is 2 meters per square second.

Explanation:

By Newton's second law, we know that force ([tex]F[/tex]), measured in newtons, is the product of mass ([tex]m[/tex]), measured in kilograms, and net acceleration ([tex]a[/tex]), measured in meters per square second. That is:

[tex]F = m\cdot a[/tex] (1)

The initial force applied in the mass is:

[tex]F = (10\,kg)\cdot \left(2.5\,\frac{m}{s^{2}} \right)[/tex]

[tex]F = 25\,N[/tex]

In addition, we know that force is directly proportional to acceleration. If the smaller force is removed, then the initial force is reduced to [tex]\frac{4}{5}[/tex] of the initial force. The acceleration of the mass is:

[tex]\frac{25\,N}{20\,N} = \frac{2.5\,\frac{m}{s^{2}} }{a}[/tex]

[tex]a = 2\,\frac{m}{s^{2}}[/tex]

The acceleration of the mass is 2 meters per square second.