Answer:
a) 513775.5 m^3 ≈ 51.38 * 10^4 m^3
b) 256887.75 m^3 ≈ 25.69 * 10^4 m^3
Step-by-step explanation:
Given data :
Depth of pond = 2m
flow in the stream = 20 cfs = 4.8931 * 10^4 m^3/day
settling rate = 0.2 m/day
rate constant ( k )= 0.2 / 2 = 0.1 / day
steady-state removal of the solids required = 65%
A) determine size of a single CSTR to achieve 65%
First determine the time required to achieve this using the relation below
C = [tex]c_{o} e^{-kt}[/tex]
∴ t = [tex]\frac{-1}{k}* ln( 1 - 0.65 )[/tex]
= ( -1 / 0.1 ) * (- 1.05 ) = 10.5 day
The size of a single CSTR required = ( 4.8931*10^4 ) * (10.5 ) = 513775.5 m^3
B) determine the sizes of a pair of identical CSTRs in series needed to achieve the desired removal
sizes of a pair = 513775.5 / 2 = 256887.75 m^3