Answer:
HEY!
THE TOTAL AREA OFTHE FIGURE = AREA OF SQUARE + AREA OF TRIANGLE
= [tex]a^{2}[/tex] +( [tex]\frac{1}{2}[/tex] x b x h)
where , [tex]a^{2}[/tex] = 19 x 19 = [tex]361 cm ^{2}[/tex]
and ( [tex]\frac{1}{2}[/tex] x b x h) = ( [tex]\frac{1}{2}[/tex] x 6 x 19) = ( [tex]\frac{1}{2}[/tex] x 114) = ( [tex]\frac{114}{2}[/tex] ) = [tex]57 cm^{2}[/tex] =
∴ [tex]361 cm ^{2}[/tex] + [tex]57cm^{2}[/tex] = [tex]418cm^{2}[/tex]
∴ 418 cm²
Hope it helped u!
