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The Achilles tendon is a fibrous tissue that connects your soleus to your calcaneus and can withstand 145 MPa of tensile stress. Assume the Achilles tendon can be modeled as a cylinder with a diameter with a diameter of 3.25 cm. How much normal tensile force (in Newtons) would the soleus need to generate to tear the Achilles tendon

Respuesta :

Answer:

 F = 1.2 10⁵ N

Explanation:

Force is defined by

          P = F / A

          F = P A

The area is

          A = π r²

the radius is half the diameter

          r = d / 2

          A = π d²/4

         

we substitute

          F = P π d²/4

let's calculate

          F = 145 10⁶  π (3.25 10⁻²)²/4

          F = 1.2 10⁵ N

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