Respuesta :
Answer:
2.5 dB/100 ft
Explanation:
If 5 dB was lost after 200 ft of cable and 100 ft is half of 200 ft, then the rate of loss should be 2.5 dB per 100 ft.
We know that the attenuation or loss for each frequency can be modeled with a proportional relation like:
y = k*x
Where k is the constant of proportionality.
We will find that the loss rate is 2.5db per 100ft.
First we know that in 200ft, the cable losts 5db.
We can replace these values in the proportional relation to find the value of k:
5db = k*200ft
k = (5db/200ft) = 0.025 db/ft
This is the loss rate per ft.
But we want to get the loss rate per 100ft.
Then we just need to multiply the rate that we got by 100.
k*100 = (0.025 db/ft)*100 = 2.5 db/(100ft)
The loss rate is 2.5db per 100ft.
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