dontmindme3
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I really need help!
A clothing business finds there is a linear relationship between the number of shirts,
n,it can sell and the price,p, it can charge per shirt. In particular, historical data shows that 2000 shirts can be sold at a price of $91, while 5000 shirts can be sold at a price of $82. Give a linear equation in the form p=mn+b that gives the price p they can charge for n shirts.

Respuesta :

Answer:

n = (-1000/3)p + (97000)/3)

Step-by-step explanation:

The data given says, in effect, that the linear equation based on price passes through 2 points (82, 5000) and (91, 2000), given two points on a line, we'll use the point-slope form to start.  To use this we must first find the slope

m = (y2 - y1) / (x2 - x1) = (2000 - 5000) / (91 - 82) = -3000 / 9 = -1000/3

(I like to leave slopes as fractions <rather than decimal> since fractions are more accurate)

point-slope form

y - y0 = m(x - x0) at some point (x0, y0) with slope m, we'll use (91, 2000)

y - 2000 = (-1000/3)(x - 91), distribute

y - 2000 = (-1000/3)x + 91000/3, add 2000 to each side

y = (-1000/3)x +97000/3

oops, substitute p for x and n for y

n = (-1000/3)p + (97000)/3)

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