Answer:
Explanation:
From the given information:
The square foundation = 3m by 3m
capacity q = 165 kPa
depth = 1.5 m
assuming soil unit weight = 17.5 kN
q = 17.5 × 1.5
q = 26.25 kPa
Settlement [tex]Se = C_1C_2 (\overline q - q) (\dfrac{I_z}{E_s})D_f[/tex]
where;
[tex]c_1 = 1-0.5 (\dfrac{q}{\overline q -q})[/tex]
[tex]c_1 = 0.905[/tex]
[tex]c_2 = 1+ 0.2 log ( \dfrac{t}{0.1})[/tex]
suppose t = 1year
[tex]c_2 = 1+ 0.2 log ( \dfrac{1}{0.1})[/tex]
[tex]c_2 = 1.2[/tex]
Using Schertmann method.
[tex]\mathtt{ I_t = 0.5 }[/tex]
[tex]\dfrac{length }{breadth } = \dfrac{3}{3}=1[/tex]
∴
E⁵ = [tex]2.5 q_e[/tex]
E⁵ = 2.5 × 165
E⁵ = 412.5 kPa
Hence: [tex]Se = C_1C_2 (\overline q - q) (\dfrac{I_z}{E_s})D_f[/tex]
[tex]Se = 0.905 * 1.2(165-26.25) (\dfrac{0.5}{412.5})*1.5[/tex]
[tex]\mathbf{Se = 0.273 \ m}[/tex]
