To what volume should you dilute 122 mL of an 8.20 M CuCl2 solution so that 51.0 mL of the diluted solution contains 4.40 g CuCl2

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26-02-2021
Chemistry

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To what volume should you dilute 122 mL of an 8.20 M CuCl2 solution so that 51.0 mL of the diluted solution contains 4.40 g CuCl2

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rathiramakanta rathiramakanta · Answer 1 · 2021-02-26T03:09:08+01:00

Answer:

The first thing to do here is to use the molarity and the volume of the initial solution to figure out how many grams of copper(II) chloride it contains.

133 mL solution

⋅

1 L

10

3 mL

⋅

7.90 moles CuCl

2

1 L solution

=

1.051 moles CuCl

2 To convert this to grams, use the compound's molar mass

1.051 moles CuCl

2 ⋅

134.45 g

1 mole CuCl

2 =

141.31 g CuCl

2 Now, you know that the diluted solution must contain

4.49 g

of copper(II) chloride. As you know, when you dilute a solution, you increase the amount of solvent while keeping the amount of solute constant.

This means that you must figure out what volume of the initial solution will contain

4.49 g

of copper(II) chloride, the solute.

4.49 g

⋅

133 mL solution

141.32 g

=

4.23 mL solution

−−−−−−−−−−−−−−

The answer is rounded to three sig figs.

You can thus say that when you dilute

4.23 mL

of

7.90 M

copper(II) chloride solution to a total volume of

51.5 mL

, you will have a solution that contains

4.49 g

of copper(II) chloride.

dsdrajlin dsdrajlin · Answer 2 · 2022-02-15T12:59:43+01:00

122 mL of 8.20 M CuCl₂ solution should be diluted to 1.56 L so that 51.0 mL of the diluted solution contains 4.40 g CuCl₂.

What is a dilution?

The act of reducing the concentration of a mixture or solution by adding solvent.

Step 1: Calculate the molarity of the diluted solution.

The diluted solution contains 4.40 g of CuCl₂ in 51.0 mL of solution.

M = mass CuCl₂ / molar mass CuCl₂ × liters of solution

M = 4.40 g / 134.45 g/mol × 0.0510 L = 0.642 M

Step 2: Calculate the volume of the diluted solution.

We have 122 mL (V₁) of 8.20 M (C₁) CuCl₂ solution and want to prepare a 0.642 M (C₂) CuCl₂ solution.

We can calculate the volume of the diluted solution (V₂) using the dilution rule.

C₁ × V₁ = C₂ × V₂

V₂ = C₁ × V₁ / C₂

V₂ = 8.20 M × 122 mL / 0.642 M = 1.56 × 10³ mL = 1.56 L

122 mL of 8.20 M CuCl₂ solution should be diluted to 1.56 L so that 51.0 mL of the diluted solution contains 4.40 g CuCl₂.

Learn more about dilution here: https://brainly.com/question/1615979