Answer:
[tex]log_e \Big (\dfrac{95}{2} \Big )= {-6w}[/tex]
Step-by-step explanation:
From the given information:
We need to find the value of w
[tex]2*e^{-6w}= 95[/tex]
Divide both sutiet sl???ides. VVVVV
[tex]e^{-6w}= \dfrac{95}{2}[/tex]
Taking the logarithim in base in e for both sides:
[tex]log_e \Big (\dfrac{95}{2} \Big )= {-6w}[/tex]
