Answer:
Area of ∆EDF = 9.6 in.²
Step-by-step explanation:
Given:
∆BAC ~ ∆EDF
Area of ∆BAC = 15 in.²
EF = 4 in.
BC = 5 in.
Required:
Area of ∆EDF
SOLUTION:
The ratio of the area of two similar shape = the ratio of the square of their corresponding side lengths
Let x represent the area of ∆EDF
Therefore:
15/x = 5²/4²
15/x = 25/16
Cross multiply
x×25 = 15×16
25x = 240
Divide both sides by 25
x = 240/25
x = 9.6
Area of ∆EDF = 9.6 in.²
