Solve the problem.
Two plumbers make house calls. One charges $105 for a visit plus $30 per hour of work. The other charges
$80 per visit plus $40 per hour of work. For how many hours of work do the two plumbers charge the same?

Respuesta :

Answer:

The two plumbers charge the same for 2.5 hours of work.

Step-by-step explanation:

The first plumber's charge is given by F(x).

The second plumber's charge is given by S(x).

One charges $105 for a visit plus $30 per hour of work.

This means that, for x hours of work, the charge is given by:

[tex]F(x) = 105 + 30x[/tex]

The other charges $80 per visit plus $40 per hour of work.

This means that, for x hours of work, the charge is given by:

[tex]S(x) = 80 + 40x[/tex]

For how many hours of work do the two plumbers charge the same?

This is x for which:

[tex]S(x) = F(x)[/tex]

So

[tex]80 + 40x = 105 + 30x[/tex]

[tex]10x = 25[/tex]

[tex]x = \frac{25}{10}[/tex]

[tex]x = 2.5[/tex]

The two plumbers charge the same for 2.5 hours of work.

Answer:

The two plumbers charge the same for 2.5 hours of work.  

The first plumber's charge is given by F(x).

The second plumber's charge is given by S(x).

One charges $105 for a visit plus $30 per hour of work.

This means that, for x hours of work, the charge is given by:

The other charges $80 per visit plus $40 per hour of work.

This means that, for x hours of work, the charge is given by:

For how many hours of work do the two plumbers charge the same?

This is x for which:

So

The two plumbers charge the same for 2.5 hours of work.