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A stationary source produces a sound wave at a frequency of 100 Hz. The wave travels at 1125 feet per second. A car is moving toward the sound source at a speed of 100 feet per second.

What is the wavelength of the stationary sound source and the wavelength that a person in the car perceives?

(1 point)

wavelength of the stationary source: 10.25 ft; perceived wavelength: 11.25 ft

wavelength of the stationary source: 11.25 ft; perceived wavelength: 10.25 ft

wavelength of the stationary source: 11.25 ft; perceived wavelength: 12.25 ft

wavelength of the stationary source: 12.25 ft; perceived wavelength: 11.25 ft me

Respuesta :

Answer:

11.25; 10.25 ft.

Explanation:

The actual wavelength and observed wavelength of the sound is required.

The correct statement is

Wavelength of the stationary source: 11.25 ft; perceived wavelength: 10.25 ft

[tex]v[/tex] = Velocity of sound = 1125 ft/s

[tex]v_o[/tex] = Velocity of observer = 100 ft/s

[tex]f_s[/tex] = Frequency at source = 100 Hz

Actual wavelength

[tex]\lambda=\dfrac{v}{f_s}\\\Rightarrow \lambda=\dfrac{1125}{100}\\\Rightarrow \lambda=11.25\ \text{ft}[/tex]

Observed frequency

[tex]f_o=f_s(\dfrac{v+v_o}{v})\\ =100(\dfrac{1125+100}{1125})\\ =\dfrac{980}{9}\ \text{Hz}[/tex]

Observed wavelength

[tex]\lambda'=\dfrac{v}{f_o}\\ =\dfrac{1125}{\dfrac{980}{9}}\\ =10.33\ \text{ft}[/tex]

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