Answer: 11.24 moles of [tex]K_3PO_4[/tex] will be produced from 5.62 moles of magnesium phosphate [tex](Mg_3(PO_4)_2)[/tex]
Explanation:
The balanced chemical equation for double displacement reaction is:
[tex]Mg_3(PO_4)_2+3K_2SO_4\rightarrow 3MgSO_4+2K_3PO_4[/tex]
According to stoichiometry :
1 mole of [tex]Mg_3(PO_4)_2[/tex] produce = 2 mole of [tex]K_3PO_4[/tex]
Thus 5.62 moles of [tex]Mg_3(PO_4)_2[/tex] will produce=[tex]\frac{2}{1}\times 5.62=11.24moles[/tex] of [tex]K_3PO_4[/tex]
Thus 11.24 moles of [tex]K_3PO_4[/tex] will be produced from 5.62 moles of magnesium phosphate [tex](Mg_3(PO_4)_2)[/tex]
The number of moles of potassium phosphate that will be produced will be 11.24 moles
Given the balanced equation expressed as:
[tex]Mg_3(PO_4)_2+ 3K_2SO_4\rightarrow 3MgSO_4+ 2K_3PO_4.[/tex]
Based on stochiometry, 1 mole of magnesium phosphate produces 2 moles of potassium phosphate
Given that there are 5.62 moles of magnesium phosphate (Mg3(PO4)2), the number of moles of potassium phosphate that will be produced will be2(5.62) = 11.24 moles
Learn more on stochiometry here: https://brainly.com/question/16060223
