Answer:
A) 80 N
Explanation:
The closer the particles get, the stronger the Coulomb force, which elongates choices C and D. The Coulomb force is inversely proportional to the distance squared. If the distance is cut in half, the force is multiplied by the reciprocal of (1/2)^2, which is 4. Multiplying it out, 20 times 4 is 80 N.
The Coulomb force if the same particles are separated by a distance of 6 meters is 222.221 N.
Coulomb force is also known as electrostatic force is the force of attraction or repulsion of particles or objects because of their electric charge. It is given by the formula,
[tex]F = k \dfrac{q_1q_2}{r^2}[/tex]
Where
F = electric force
k = Coulomb constant = 8.9875517923×10⁹ kg⋅m³⋅s⁻²⋅C⁻²
[tex]q_1, q_2[/tex] = charges
r = distance of separation
We know that the distance between the two particles is 12 meters while the force between the two particles is 20N, therefore, the Coulombs force can be written as,
[tex]F = k \dfrac{q_1q_2}{r^2}\\\\20 = k \dfrac{q_1q_2}{20^2}\\\\k {q_1q_2} = 20 \times 20^2\\\\k {q_1q_2} = 8000[/tex]
Now, if the distance between the two particles is reduced to 6, the force will be,
[tex]F = k \dfrac{q_1q_2}{r^2}\\\\F = \dfrac{8000}{6^2}\\\\F = 222.221\rm\ N[/tex]
Hence, the Coulomb force if the same particles are separated by a distance of 6 meters is 222.221 N.
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