The measure of BC is 24 cm. So, option B is correct.
Important information:
- The diagram of a circle A with two tangents.
- Radius of circle A is 10 cm.
- AC = 26 cm
We need to find the measure of BC.
Tangent to circle:
We have,
AD = AB = 10 cm
We know that the radius of a circle is perpendicular to the tangent at the point of tangency. It means triangle ABC is a right angle triangle.
Using the Pythagoras theorem, we get
[tex](AB)^2+(BC)^2=(AC)^2[/tex]
[tex](10)^2+(BC)^2=(26)^2[/tex]
[tex](BC)^2=676-100[/tex]
[tex](BC)^2=576[/tex]
Taking square root on both sides, we get
[tex]BC=\sqrt{576}[/tex]
[tex]BC=24[/tex]
The measure of BC is 24 cm. So, option B is correct.
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