contestada

A gas is at a pressure of 97.0 kPa and has a volume of 0.4 L If the pressure increased to 178 kPa, what
will be the new volume? (Temp is constant)
Equation: P1V1 = P2V2
1.36 L
0.73 L
0.22 L
431 L

Respuesta :

Space

Answer:

V₂ ≈ 0.22 L

General Formulas and Concepts:

Math

Pre-Algebra

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right  

Equality Properties

  • Multiplication Property of Equality
  • Division Property of Equality
  • Addition Property of Equality
  • Subtraction Property of Equality

Chemistry

Gas Laws

  • Pressure
  • Boyle's Law: P₁V₁ = P₂V₂

Explanation:

Step 1: Define

[Given] P₁ = 97.0 kPa

[Given] V₁ = 0.4 L

[Given] P₂ = 178 kPa

[Solve] V₂

Step 2: Solve for V₂

  1. Substitute in variables [Boyle's Law]:                                                              (97.0 kPa)(0.4 L) = (178 kPa)V₂
  2. [Boyle's Law] Multiply:                                                                                      38.8 kPa · L = (178 kPa)V₂
  3. [Boyle's Law] [Division Property of Equality] Isolate V₂ [Cancel units]:         0.217978 L = V₂
  4. [Boyle's Law] [Volume] Rewrite:                                                                      V₂ = 0.217978 L
  5. [Boyle's Law] [Volume] Round:                                                                        V₂ ≈ 0.22 L

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