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The length of a rectangle is 1 foot more than twice the width. The area is 55 square feet. Find the perimeter of the rectangle.

Respuesta :

Answer:

5 ft and 11 ft

Step-by-step explanation:

l= 2w+1

A=lw= 55

w(2w+1)=55

2w²+w-55=0

integer solution of quadratic equation is:

w=5 ft

l= 2*5+1=11 ft

Answer:

32 feet

Step-by-step explanation:

Start by creating your 2 equations

l = 2w + 1

l * w = 55

Plug in l, the isolated variable

(1 + 2w)w = 55

w + 2w² = 55

2w² + w -55 = 0

( − 5 ) ( 2 + 1 1 ) = 0

w= 5

w= -11/2 <- the width can't be negative so this one is out

Plug width into the area formula to find length

l * 5 = 55

l = 11

Find the Perimeter

2(11) + 2(5)

22 + 10 = 32