Answer:
Q = 0.768 calorie
Explanation:
Given that,
Mass of water, m = 18.2g
The temperature changes from 25.2°C to 67.4 °C.
The specific heat of water, c = 4.184 J/g °C
We need to find the heat needed to change in temperature. The formula is given by :
[tex]Q=mc\Delta T\\\\Q=18.2\times 4.184\times (67.4-25.2)\\\\Q=3213.47\ J[/tex]
We know that, 1 calorie = 4184 J
or
1 J = (1/4184) calories
t means,
[tex]3213.47\ J=\dfrac{3213.47}{4184}\ J\\\\=0.768\ calorie[/tex]
So, the required heat needed is 0.768 cal.
So, 0.768 calorie of heat is needed.
