In the diagram below DE is the midsegment of AABC.
Find the length of DE and BC.

Answer:
DE = 5
BC = 10
Step-by-step explanation:
ΔAED is a right triangle with legs of 4 and 6/2 = 3
Use the Pythagorean theorem to find DE
[tex]4^{2} + 3^{2} = DE^{2}[/tex]
16 + 6 = 25 = [tex]DE^{2}[/tex]
DE = 5
The midsegment of a triangle is 1/2 the length of the corresponding side.
Therefore, BC = 2 DE = 2(5) = 10 = BC