Find an equation of the tangent line to the curve at the given point. y=√x, (49,7) To find the equation of a line, we need the slope of the line and a

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Answer:

The equation of the tangent line to the curve at the given point is [tex]y = \frac{1}{14}(x - 49) + 7[/tex]

Step-by-step explanation:

Equation of the tangent line:

The equation of the tangent line to a function f(x) at a point [tex](x_0,y_0)[/tex] is given by:

[tex]y - y_0 = m(x - x_0)[/tex]

In which m is the slope, which is given by the derivative of f(x) at [tex]x_{0}[/tex]

y=√x, (49,7)

This means that [tex]x_0 = 49, y_0 = 7[/tex]

The derivative is:

[tex]y^{\prime} = \frac{1}{2\sqrt{x}}[/tex]

At [tex]x = 49[/tex]

[tex]m = y^{\prime} = \frac{1}{2\sqrt{49}} = \frac{1}{14}[/tex]

So

[tex]y - y_0 = m(x - x_0)[/tex]

[tex]y - 7 = \frac{1}{14}(x - 49)[/tex]

[tex]y = \frac{1}{14}(x - 49) + 7[/tex]

The equation of the tangent line to the curve at the given point is [tex]y = \frac{1}{14}(x - 49) + 7[/tex]