At 4 PM, the level of the water in the lake was 10 feet. At 8 PM, the level of the water was 2 feet. Determine the constant rate of change of the water.

Respuesta :

Answer:

[tex]-4\ \text{feet/hour}[/tex]

Step-by-step explanation:

Level of water at 4 PM is 10 feet.

Level of water at 8 PM is 2 feet.

Time duration in which water level is measured is [tex]8-4=4\ \text{hours}[/tex]

The change of the level of water in the given time duration is [tex]2-10=-8\ \text{feet}[/tex]

The rate of change would be

[tex]R=\dfrac{-8}{4}=-4\ \text{feet/hour}[/tex]

The constant rate of change of the water is [tex]-4\ \text{feet/hour}[/tex].

The minus sign indicates that the water level is reducing.