Answer: 0.055 moles of [tex]O_2[/tex] are produced by the reaction of 0.055 mol of ammonium perchlorate.
Explanation:
The balanced chemical reaction for decomposition of ammonium perchlorate is:
[tex]2NH_4ClO_4\rightarrow N_2+Cl_2+2O_2+4H_2O[/tex]
According to stoichiometry :
2 moles of [tex]NH_4ClO_4[/tex] produce = 2 moles of [tex]O_2[/tex]
Thus 0.055 moles of [tex]NH_4ClO_4[/tex] will produce =[tex]\frac{2}{2}\times 0.055=0.055moles[/tex] of [tex]O_2[/tex]
Thus 0.055 moles of [tex]O_2[/tex] are produced by the reaction of 0.055mol of ammonium perchlorate.