Answer: 0.45 moles of water are needed to produce 0.075mol of glucose.
Explanation:
The balanced chemical reaction is:
[tex]6CO_2(g)+6H_2O(l)\rightarrow C_6H_{12}O_6(aq)+6O_2(g)[/tex]
According to stoichiometry :
1 mole of glucose require = 6 moles of [tex]H_2O[/tex]
Thus 0.075 moles of glucose require = [tex]\frac{6}{1}\times 0.075=0.45[/tex] moles of [tex]H_2O[/tex]
0.45 moles of water are needed to produce 0.075mol of glucose.