Answer: 3881 g of [tex]Cl_2[/tex] will be produced along with 109.34 moles of Na
Explanation:
The balanced chemical equation is:
[tex]2NaCl(s)\rightarrow 2Na(s)+Cl_2(g)[/tex]
According to stoichiometry :
2 moles of [tex]Na[/tex] are produced along with = 1 mole of [tex]Cl_2[/tex]
Thus 109.34 moles of [tex]Na[/tex] will produced along with=[tex]\frac{1}{2}\times 109.34=54.67moles[/tex] of [tex]Cl_2[/tex]
Mass of [tex]Cl_2=moles\times {\text {Molar mass}}=54.67moles\times 71g/mol=3881g[/tex]
Thus 3881 g of [tex]Cl_2[/tex] will be produced along with 109.34 moles of Na
