Ben starts walking along a path at 2 mi/h. One and a half hours after Ben leaves, his sister Amanda begins jogging along the same path at 7 mi/h. How long (in hours) will it be before Amanda catches up to Ben?

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Answer:

Amanda will catch up Ben after 0.6 hours.

Step-by-step explanation:

Amanda begins jogging along the same path at 7 mi/h.

This means that Amanda's position, after t hours, is given by:

[tex]A(t) = 7t[/tex]

Ben starts walking along a path at 2 mi/h.

Amanda leaves after one and a half hour, which means that Ben will be at position 2*1.5 = 3. So Ben's position after t hours is given by:

[tex]B(t) = 3 + 2t[/tex]

How long (in hours) will it be before Amanda catches up to Ben?

This will happen when:

[tex]A(t) = B(t)[/tex]

So

[tex]7t = 3 + 2t[/tex]

[tex]5t = 3[/tex]

[tex]t = \frac{3}{5}[/tex]

[tex]t = 0.6[/tex]

Amanda will catch up Ben after 0.6 hours.

It would take Amanda 0.6 hours or 6/10 hours to catch up with Ben.

This question comes from a topic in mathematics called rates and it's used to compare two values with each other and how one value affects the other value.

Let s represent the distance Amanda travels until she meet Ben.

We can set a timer on our phone when she leaves in order to track the time taken.

Let t represent the time taken.

Set of Equation

We can come up with two equations from these scenario

  • d - 3 = 2t------ equation (i)
  • d = 7t ----- equation (ii)

Substitute equation (ii) into equation (i)

[tex]7t -3 =2t[/tex]

collect like terms

[tex]7t-2t=3\\5t=3\\t=3/5\\t=0.6[/tex]

From the above, we can see it took her 0.6 hours to catch up with Ben.

Learn more about rates here;

https://brainly.com/question/14323743