Answer: The total pressure, in atm is 2.62
b. The mole fraction of argon in the container is 0.67.
Explanation:
a) According to Dalton's law, the total pressure is the sum of individual pressures.
[tex]p_{total}=p_A+p_B+p_C...[/tex]
Given : [tex]p_{total}[/tex] =total pressure of gases = ?
[tex]p_{F_2}[/tex] = partial pressure of fluorine = 0.85 atm
[tex]p_{Ar}[/tex] = partial pressure of Argon = 1350 torr = 1.77 atm ( 760 torr = 1atm)
putting in the values we get:
[tex]p_{total}=0.85atm+1.77atm=2.62atm[/tex]
b) According to Raoult's law, the partial pressure of a component at a given temperature is equal to the mole fraction of that component multiplied by the total pressure.
[tex]p_{Ar}=x_{Ar}p_{total}[/tex]
where, x = mole fraction
[tex]1.77atm=x_{Ar}\times 2.62atm[/tex]
[tex]x_{Ar}=0.67[/tex]
The mole fraction of argon in the container is 0.67.
