Answer:
[tex]x=6,y=42[/tex]
Step-by-step explanation:
The equations are
[tex]y=5x+12[/tex]
[tex]3y+4x=150[/tex]
Substituting the first equation in the second we get
[tex]3(5x+12)+4x=150[/tex]
[tex]\Rightarrow 15x+36+4x=150[/tex]
[tex]\Rightarrow x=\dfrac{150-36}{19}[/tex]
[tex]\Rightarrow x=6[/tex]
[tex]y=5x+12=5\times 6+12\\\Rightarrow y=42[/tex]
So, the required values are [tex]x=6,y=42[/tex]
