Explanation:
Answer
( 58.3 mL ) (
0.789 g
1 mL
) (
1 mole
46 g
) = 1 mole C2H5OH
( 500 mL H2O ) (
1 g
1 mL
) (
1 mole
18 g
) = 27.8 mole H2O
The total moles = 1 mole C2H5OH + 27.8 mole H2O = 28.8 moles
The mole fraction =
moles C2H5OH
total moles
=
1 mole C2H5OH
28.8 total moles
= 0.035
The mole percent would be 3.5%.
What is the weight fraction?
Answer
( 58.3 mL ) (
0.789 g
1 mL
) = 46 g C2H5OH
( 500 mL H2O ) (
1 g
1 mL
) = 500 g H2O
The total mass = 46 g C2H5OH + 500 g H2O = 546 g
The mass fraction =
mass C2H5OH
total mass
=
46 g C2H5OH
546 total grams
= 0.084
The mass percent would be 8.4%.
What is the molarity?
Answer
The molarity =
moles C2H5OH
L of solution
=
1 mole C2H5OH
.5583 L
= 1.79 M
What is the molality?
Answer
The molality =
moles C2H5OH
kg of solvent
=
1 mole C2H5OH
0.5 kg H2O
= 2
