6sin^2theta = 7- 5costheta
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Answer:
6sin^2(x) = 7 - 5cos(x)
6(1 - cos^2(x)) = 7 - 5cos(x)
6 - 6cos^2(x) = 7 - 5cos(x)
6cos^2(x) + 5cos(x) -1 = 0
(6cos(x) - 1)(cos(x) + 1) = 0
cos(x) = 1/6
x = arccos(1/6)
x = 1.40334825 + 2k*pi, 4.87983706 + 2k*pi
cos(x) = -1
x = pi + 2k*pi