Respuesta :
Answer:
100 individuals will have attached earlobes out of a population of 10000
Explanation:
From the Hardy-Weinberg equilibrium; p² + 2pq + q². Also, p + q = 1
p² = population of individuals breeding true for free earlobes
2pq = population of individuals heterozygous for free earlobes
q² = population of individuals breeding true for attached earlobes
p = frequency of dominant allele
q = frequency of recessive allele
The dominant trait is free earlobes while the recessive trait is attached earlobes.
Eight out of ten are breed-true for free earlobes, whereas, two were heterozygous for that trait.
p² = 8/10 = 0.8
p = 0.89 or approximately 0.9
q = 1 - p
q = 1 - 0.9
q = 0.1
q² = (0.1)²
q² = 0.01
For a population of 10000 persons, number of people with attached earlobes will be:
0.01 * 10000 = 100 persons
Therefore, 100 individuals will have attached earlobes out of a population of 10000