Answer:
%C = 54.53%
%H = 9.144%
%O = 36.32%
Explanation:
Step 1: Calculate the mass of each element in 1 mole of C₄H₈O₂
We will multiply the number of atoms by the molar mass of the element.
mC: 4 × 12.01 g = 48.04 g
mH: 8 × 1.007 g = 8.056 g
MO: 2 × 16.00 g = 32.00 g
Step 2: Calculate the mass of 1 mole of C₄H₈O₂
We will sum the previously calculated masses of the elements.
mC₄H₈O₂ = mC + mH + mO = 48.04 g + 8.056 g + 32.00 g = 88.10 g
Step 3: Calculate the percent composition of each element
We will use the following expression.
%Element = mElement / mCompound × 100%
%C = 48.04 g / 88.10 g × 100% = 54.53%
%H = 8.056 g / 88.10 g × 100% = 9.144%
%O = 32.00 g / 88.10 g × 100% = 36.32%
