Answer:
[tex]n=4.68\times 10^{18}[/tex]
Explanation:
The current through the bulb, I = 0.75 A
We need to find the number of electrons flowing per second. We know that the electric current is given by :
[tex]I=\dfrac{ne}{t}\\\\n=\dfrac{It}{e}\\\\n=\dfrac{0.75\times 1}{1.6\times 10^{-19}}\\\\n=4.68\times 10^{18}[/tex]
So, there are [tex]4.68\times 10^{18}[/tex] electrons flowing per second.
There are "[tex]4.68\times 10^{18}[/tex]" electron flowing per second.
Whenever retained inside an electric as well as the magnetic field, this same basic physical attribute of matter which thus permits it to perceive a force, is considered as Electric charge.
According to the question,
Current flow, I = 0.75 A
Electric charge of one electron, e = 1.6 x 10⁻¹⁹ C
As we know the relation,
Current, I = [tex]\frac{ne}{t}[/tex]
or,
→ n = [tex]\frac{It}{e}[/tex]
By substituting the given values in the above formula, we get
= [tex]\frac{0.75\times 1}{1.6\times 10^{-19}}[/tex]
= [tex]4.68\times 10^{18}[/tex]
Thus the approach above is appropriate.
Find out more information about electric charge here:
https://brainly.com/question/14372859
