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A 3 L pocket of air at sea level has a pressure of 100 atm. Suppose the air pockets rise in the atmosphere to a certain height and expands to a volume of 10 L. What is the pressure of the air at the new volume?

Respuesta :

Answer:

30 atm

Explanation:

Initial Volume, V1 = 3L

Initial Pressure, P1 = 100 atm

Final Volume V2 = 10 L

Final Pressure, P2 = ?

These quantities are related by the Boyle's law equation which is given as;

V1P1 = V2P2

P2 = V1 * P1  /  V2

P2 = 3 * 100 / 10

P2 = 30 atm

The study of chemicals is called chemistry.

The correct answer is 30 atm.

The ideal gas law is stated as the equation of the state of a hypothetical ideal gas. It is a good approximation of the behavior of many gases under many conditions, although it has several limitations.

The data given in the question is as follows:-

  • Initial Volume, V1 = 3L
  • Initial Pressure, P1 = 100 atm
  • Final Volume V2 = 10 L

We have to find the final Pressure, To solve this question the formula is used as follows:-

[tex]V_1P_1 = V_2P_2\\\P_2 = \frac{V_1 * P_1 }{V_2}[/tex]

[tex]P_2 = \frac{3 * 100}{ 10}\\P_2 = 30 atm[/tex].

Hence, the correct answer is 30 atm.

For more information, refer to the link;-

https://brainly.com/question/14698383

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