What is the equation of a circle with the center (2,3) that passes through the point (5,3)

The given center and point on the circle of (2, 3), and (5, 3), respectively
gives the equation of the circle as; [tex]\underline{(x - 2)^2 + (y - 3)^2 = 3^2}[/tex].
The general form of the equation of the circle is presented as follows;
(x - h)² + (y - k)² = r²
Where;
(h, k) = The center of the circle
r = The radius of the circle
Which gives;
(h, k) = (2, 3)
h = 2
k = 3
r = √((5 - 2)² + (3 - 3)²) = 3
The equation of the circle is therefore;
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