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A circus stuntman holds himself straight out by his arms from a vertical pole. If the stuntman's center of gravity is located 0.75 m away from the pole and he weights 650 N, how much force do is arms have to apply if they exert their force upwards at 0.10 m away from the pole? [4875 N]

Respuesta :

Answer: 4875 N

Explanation:

Given

Stuntman weight is [tex]W=650\ N[/tex]

His center of gravity is located at [tex]x=0.75\ m[/tex] away from pole

If he applies an upwards force at 0.10 m away from the pole

Suppose  F is the applied force

To remain vertical, the torque of weight must be canceled by the vertical force

[tex]\Rightarrow 650\times 0.75-F\times 0.10=0\\\\\Rightarrow 650\times 0.75=F\times 0.10\\\\\Rightarrow F=\dfrac{487.5}{0.10}=4875\ N[/tex]

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