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Select all the equations that have no solution and state your reasoning as of "why" they do not have a solution. +6=5+ x+6=5+x −2(−3)=-2+6 −2(x−3)=-2x+6 4−4=3+2 4−4x=3x+2 4(+1)=3(+2) 4(x+1)=3(x+2) 5−3=-3+4 5−3x=-3x+4

Respuesta :

MrRoyal

Equations:

[tex]x+6=5+x[/tex]

[tex]-2(x-3)=-2x+6[/tex]

[tex]4-4x=3x+2[/tex]

[tex]4(x+1)=3(x+2)[/tex]

[tex]5-3x=-3x+4[/tex]

Answer:

[tex]x+6=5+x[/tex]

[tex]5-3x=-3x+4[/tex]

Step-by-step explanation:

Given

[tex]x+6=5+x[/tex]

[tex]-2(x-3)=-2x+6[/tex]

[tex]4-4x=3x+2[/tex]

[tex]4(x+1)=3(x+2)[/tex]

[tex]5-3x=-3x+4[/tex]

Required:

Which have no solution

[tex]x+6=5+x[/tex]

Subtract x from both sides

[tex]x -x+6 = 5 + x - x[/tex]

[tex]6 = 5[/tex]

[tex]x+6=5+x[/tex] has no solution because [tex]6 \ne 5[/tex]

[tex]-2(x-3)=-2x+6[/tex]

Open bracket

[tex]-2x + 6 = -2x + 6[/tex]

Both sides are equal.

Hence, there is an [tex]Infinite\ Number[/tex] of Solutions

[tex]4-4x=3x+2[/tex]

Collect like terms

[tex]-3x - 4x = 2 - 4[/tex]

[tex]-7x = -2[/tex]

Solve for x

[tex]x = \frac{-2}{-7}[/tex]

[tex]x = \frac{2}{7}[/tex] --- This has a solution

[tex]4(x+1)=3(x+2)[/tex]

Open brackets

[tex]4x + 4 = 3x + 6[/tex]

Collect like terms

[tex]4x-3x = 6 - 4[/tex]

[tex]x = 2[/tex] --- This has a solution

[tex]5-3x=-3x+4[/tex]

Add 3x to both sides

[tex]5 - 3x + 3x = -3x + 3x + 4[/tex]

[tex]5 = 4[/tex]

[tex]5-3x=-3x+4[/tex] has no solution because [tex]5 \ne 4[/tex]

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