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A cement mixer with a radius of 2 m spins with a tangential velocity of 0.4 m/s. Determine the centripetal acceleration of a piece of dried cement stuck to the inside wall of the mixer.

Respuesta :

Answer:

[tex]a=0.08\ m/s^2[/tex]

Explanation:

Given that,

The radius of the mixer, r = 2 m

Tangential velocity of the mixer, v = 0.4 m/s

We need to find the centripetal acceleration of a piece of dried cement stuck to the inside wall of the mixer. The formula for the centripetal acceleration is given by :

[tex]a=\dfrac{v^2}{r}\\\\a=\dfrac{(0.4)^2}{2}\\\\a=0.08\ m/s^2[/tex]

So, the centripetal acceleration is equal to [tex]0.08\ m/s^2[/tex].

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