hey can you state what's wrong in the given solution.

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[tex]0 = 0[/tex]

we know, zero is always equal to zero

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[tex]16 - 16 = 20 - 20[/tex]
because, 16 - 16 = 0
and 20 - 20 = 0

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taking 4 as common from 16 - 16 and 5 as common from 20 - 20
[tex]4(4 - 4) = 5(4 - 4)[/tex]
now dividing both sides by
(4 - 4)

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[tex] \frac{4(4 - 4)}{(4 - 4)} = \frac{5(4 - 4)}{(4 - 4)} [/tex]
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[tex]4 = 5[/tex]
because, (4 - 4) in denominators of both sides cancels out (4 - 4) in numerator of both sides.

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[tex]2 + 2 = 5[/tex]
we know, 4 = 2 + 2 , so plugging (2 + 2) in place of 4

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