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A compound is found to contain 52.13 % carbon , 13.15 % hydrogen , and 34.72 % oxygen by mass.
To answer the question, enter the elements in the order presented above.
QUESTION 1:
The empirical formula for this compound is
QUESTION 2:
The molar mass for this compound is 46.08 g/mol.
The molecular formula for this compound is

Respuesta :

Answer:

C2H60 & X2H60

Explanation:

Divide by the molar mass

Moles C= 53.13 g/ 12.011 g/mol =4.34

Moles H= 13.5 g/ 1.008 g/ mol= 13.4

Moles O= 34.72 g/ 15.999 g/ mol=2.170

Divide by the smallest

4.34 /2.17 =2 => C

13.4 / 2.17= 6=>H

2.170 / 2.17= 1=>O

The empirical formula is C2H60 (molar mass =46.08 g/mol)

X2H60 is also the molecular formula