mandyb2003
contestada

4NH3(g) + 5O2(g) -> 4NO(g) + 6H2O(g)


How many moles of ammonia (NH3) are needed if 2.75 moles of water (H2O) were produced?

4.13 mol

1.83 mol

4 mol

(only respond if you have the answer)

6.8 mol

Respuesta :

keijosalonen

Answer: from multipliers of substances and real amount of moles you get an equation

For x = amount of ammonia in moles. X/4 = 2.75/6 and x = 11/6 = 1.83 mol

Explanation:

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