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A screen door spring is stretched
0.299 m, and exerts a 64.7 N force
on the door. What is the spring
constant of the spring?
(Unit = N/m)

Respuesta :

OverpoweredNoob

Answer:

216.39 N/m

Explanation:

F = 64.7 N

x = 0.299 m

Plug those values into Hooke's Law:

F = kx

64.7 N = k(0.299 m)

---> k = 216.39 N/m

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