201432155
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An ant and a beetle are sitting at the south east corner of a rectangular picture frame. After a piece of sugar is placed on the north west corner they simultaneously start moving towards the sugar. The ant is moving around the frame 1.5 times faster than the beetle who is crossing the picture on a diagonal. If the length of the frame is 8 inches and the width is 1 inch more than half of diagonal, who will get to the sugar first?


PLSSSS HELP!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

I'LL GIVE BRAINLIEST!!!!!!!!!!!!!!!!!!!

Respuesta :

Answer:

Ant will get there first, ant's path is 14 in, beetle's is 10 in.

Step-by-step explanation:

if the beetle's path is 10 inches (used Pythagorean theorem to find), we now know that:

Length = 8 in

Width = 1/2 (10) + 1 = 5+1 = 6

The ant moves around the frame, so 8 in +6 in = 14 in.

Hope this helps

Here ant should get sugar first.

Calculation of the inches:

The path of the bettle should be 10 inches

And, the path of the ant should be

= length of the frame + (half of 10 + 1)

= 10  + (0.5 of 10 + 1)

= 10 +  5 + 1

= 16

So based on this, we can conclude that Here ant should get sugar first.

Learn more about length here: https://brainly.com/question/15844891

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