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Given the equation of a circle, (x - 6)^2 + (y + 7)^2 = 64, what would the
center and radius of the circle be?

A: (6,-7); r = 64
B: (6,-7); r = 8
C: (-6, 7); r = 8
D: (6,-7); r = 32

Respuesta :

Answer:

B

Step-by-step explanation:

Set x-6 and y+7 equal to zero to find the center

[tex]x - 6 = 0[/tex]

[tex] = 6[/tex]

[tex]y + 7 = 0[/tex]

[tex]y = - 7[/tex]

So the center is (6,-7)

Take the square root of the right side to find the radius.

[tex] \sqrt{64} = 8[/tex]

The answer is B

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