1.56 mole of H₂SO₄ is present in the solution.
Molarity is defined as the mole of solute per unit litre of the solution. Mathematically, it is expressed as:
[tex]Molarity = \frac{mole}{volume }[/tex]
With the above formula, we can obtain the number of mole of H₂SO₄ present in the solution. This can be obtained as follow:
Volume = 1.63 L
Molarity = 0.954 M
Mole of H₂SO₄ =?
[tex]Molarity = \frac{mole}{Volume}\\\\0.954 = \frac{mole}{1.63}[/tex]
Cross multiply
Mole = 0.954 × 1.63
Mole of H₂SO₄ = 1.56 mole
Therefore, 1.56 mole of H₂SO₄ is present in the solution.
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