Answer:
z = 8
Area of trapezoid HJKM = 69 Sq m
Step-by-step explanation:
1)
(3 + 4) + z = (4 + 8) + 3
7 + z = 15
z = 15 - 7
z = 8
2)
Area of trapezoid HJKM= Area of rectangle with dimensions 7 m and 6 m + Area of trapezoid with bases 6m, 3m and height 6 m
[tex] = 7 \times 6 + \frac{1}{2} (6 + 3) \times 6 \\ \\ = 42 + 9 \times 3 \\ \\ = 42 + 27 \\ \\ = 69 \: {m}^{2} [/tex]
