What is the length of a diagonal of a square with a side length of 8?
A. 4
B. 42
C. 43
D. 82

Answer:
D. 8[tex]\sqrt{2}[/tex]
Step-by-step explanation:
To find the diagonal of the square, you can use the Pythagorean theorem* to find the hypotenuse since the diagonal cuts the square into two right triangles with legs of 8 units in length:
If in a^2 + b^2 = c^2, a = 8 and b = 8,
8^2 + 8^2 = c^2 (put 8 as both the leg lengths in the equation)
128 = c^2 (calculate 8^2 and then add the two terms together)
c = 8[tex]\sqrt{2}[/tex] (square both sides)
So, the length of the diagonal is 8[tex]\sqrt{2}[/tex] units
*the Pythagorean theorem is a theorem used to find the sides lengths of a right triangle: a^2 + b^2 = c^2. a and b are the legs of the triangle, and c is the hypotenuse.