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3) A 6.1 kg bowling bowl and a 7.2 kg bowling ball rest on a rack. If the force of gravity pulling each
bowling ball toward the other is 3.1 X 10° N, what is the separation between the balls?

Respuesta :

asuwafohjames

The distance of separation of the balls is 3.07×10⁻⁵ m.

To Solve the question, we use the formula below.

Formula:

  • F = GMm/r²...................... Equation 1

Where:

  • F = Force of gravity
  • G = Universal constant
  • M = mass of the bigger bowling ball
  • m = mass of the smaller bowling ball
  • r = Distance of separation between the balls.

Make r the subject of the equation,

  • r = √(GMm/F)................. Equation 2

From the question,

Given:

  • F = 3.1 N
  • M = 7.2 kg
  • m = 6.1 kg
  • G = Constant = 6.67×10⁻¹¹ Nm²/kg².

Substitute these values into equation 2

  • r = √(7.2×6.1×6.67×10⁻¹¹/3.1)
  • r = √(9.45×10⁻¹⁰)
  • r = 3.07×10⁻⁵ m

Hence, the distance of separation of the balls is 3.07×10⁻⁵ m.

Learn more about gravitation force here: https://brainly.com/question/2537310

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