Answer:
v₀ₓ = 28.6 m / s
Explanation:
This is a missile throwing exercise
y = [tex]v_{oy}[/tex] t - ½ g t²
as the dart is thrown horizontally the vertical velocity is zero (I go = 0)
y = - ½ g t²
t = [tex]\sqrt{- \frac{2y}{g} }[/tex]
let's calculate
t = [tex]\sqrt{- \frac{2 \ (-0.150)}{9.8} }[/tex]
t = 0.175 s
the expression for horizontal displacement is
x = v₀ₓ t
v₀ₓ = x / t
v₀ₓ = 5.00 / 0.175
v₀ₓ = 28.6 m / s
