contestada

You are crouched at the "start" line. Bang! The race begins and 7 seconds later you end up 60 yards down the track. What was your "acceleration?"

Respuesta :

Answer:

a = 7.35 ft / s²

Explanation:

For this exercise we must use the kinematics relations

        x = v₀ t + ½ a t²

as the runner leaves the starting line his initial velocity is zero

        x = ½ a t²

        a = [tex]\frac{2x}{t^2}[/tex]

let's reduce the distance to foot

        x = 60 yd (3ft / 1yd) = 180 ft

let's calculate

         a = 2 180 / 7²

         a = 7.35 ft / s²