Answer (assuming it can be in slope-intercept form):
[tex]y = -\frac{6}{5} x+3[/tex]
Step-by-step explanation:
1) First, use the slope formula [tex]m =\frac{y_2-y_1}{x_2-x_1}[/tex] to find the slope of the line. Substitute the x and y values of the given points into the formula and solve:
[tex]m =\frac{(-3)-(3)}{(5)-(0)} \\m = \frac{-3-3}{5-0}\\m = \frac{-6}{5}[/tex]
So, the slope is [tex]-\frac{6}{5}[/tex].
2) Now, use the slope-intercept formula [tex]y = mx + b[/tex] to write the equation of the line in slope-intercept form. All you need to do is substitute real values for the [tex]m[/tex] and [tex]b[/tex] in the formula.
Since [tex]m[/tex] represents the slope, substitute [tex]-\frac{6}{5}[/tex] for it. Since [tex]b[/tex] represents the y-intercept, substitute 3 for it. (Remember, the y-intercept is the point at which the line hits the y-axis. All points on the y-axis have an x-value of 0. Notice how the given point (0,3) has an x-value, too, so it must be the line's y-intercept.) This gives the following equation and answer:
[tex]y = -\frac{6}{5} x+3[/tex]
